This will show you how to correctly link the creator of an item to their mysite in a Content Query WebPart.
Step 1:
Declare the variable “authormysite” and the author string of “UserLookup”. We pull the “Login” parameter, because the username is what is appended on the mysite link out of the box.
<xsl:variable name="authormysite">
<xsl:value-of select="ddwrt:UserLookup(string(@Author) ,'Login')" />
</xsl:variable>
Step 2:
Create the link to the mysite page, appending the new variable’s value that you just created.
< a href="https://m.isb.bj.edu.cn/Person.aspx?accountname={$authormysite}" ></ a>
Step 3:
Within the link, you want to declare the value of @Author to get their full display name.
<xsl:value-of select="@Author" />
Final code:
<xsl:template name="mysitelink" match="Row[@Style='mysitelink']" mode="itemstyle">
<xsl:variable name="authormysite">
<xsl:value-of select="ddwrt:UserLookup(string(@Author) ,'Login')" />
</xsl:variable>
< a href="https://m.isb.bj.edu.cn/Person.aspx?accountname={$authormysite}">
<xsl:value-of select="@Author" />
</ a>
</xsl:template>

Hi Ben,
i tried your solution for our search center so users can click on authors name in the results to be redirected to the authors’ mysite but didn’t get it to run.
I get the error that the webpart can’t be shown.
Here’s a snippet of my edited XSL:
<!–
–>
I hope you can help me.
I see HTML-Tags are disabled so i removed the first brackets( in hope it will work now):
div class=”srch-Metadata2″>
xsl:template name=”mysitelink” match=”Row[@Style='mysitelink']” mode=”itemstyle”>
xsl:variable name=”authormysite”>
xsl:value-of select=”ddwrt:UserLookup(string(@Author) ,’Login’)” />
/xsl:variable>
a href=”https://m.isb.bj.edu.cn/Person.aspx?accountname={$authormysite}”>
xsl:value-of select=”@Author” />
/a>
/xsl:template>
xsl:with-param name=”author” select=”author” />
/xsl:call-template>–>
xsl:call-template name=”DisplayDate”>
xsl:with-param name=”write” select=”write” />
/xsl:call-template>